2x^2/3-3x^1/3-5=0

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Solution for 2x^2/3-3x^1/3-5=0 equation: 


x in (-oo:+oo)

(2*x^2)/3-((3*x^1)/3)-5 = 0

(2*x^2)/3-x-5 = 0

2/3*x^2-x-5 = 0

DELTA = (-1)^2-(-5*2/3*4)

DELTA = 43/3

DELTA > 0

x = ((43/3)^(1/2)+1)/(2/3*2) or x = (1-(43/3)^(1/2))/(2/3*2)

x = 3/4*((43/3)^(1/2)+1) or x = 3/4*(1-(43/3)^(1/2))

x in { 3/4*(1-(43/3)^(1/2)), 3/4*((43/3)^(1/2)+1) }

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